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You are going to ligate the 1.9 kb PCR fragment (some of the DNA was removed by the restriction enzymes) in an 5.7-kb plasmid that contains an Ampicillin resistance gene. The ligation protocol you use states you need to combine the plasmid and insert in a 1:2 molar ratio, and that you need to use 100 ng of plasmid DNA.How much PCR product will you need to use as insert for this ligation?
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