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Sejam dadas as equações termoquímicas, todas a 25 ºC e 1 atm:I- H2(g)+ ½O2(g) →H2O(l) ∆H = -68,3 Kcal/molII- 2Fe(s)+ 3/2 O2(g)→Fe2O3(s) ∆H = -196,5 Kcal/molIII- 2Al(s)+ 3/2 O2(g)→Al2O3(s) ∆H = -399,1 Kcal/molIV - C(grafite)+ O2(g)→ CO2(g) ∆H = -94,0 Kcal/molV- CH4(g) + O2(g) → CO2(g)+ H2O(l) ∆H = -17,9 Kcal/molExclusivamente sob o ponto de vista energético, das reações acima, a que você escolheria como fonte de energia é:a) I.b) II.c) III.d) IV.e) V.
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