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Les modèles de réponse à l'tem à 2 paramètres modélisant la probabilité d'observer une réponse correcte en fonction de la difficulté de l'item et de l'importance des réponses au hasard
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- 一种特殊的算法, int start = 0, end = n - 1; int i = 0; while (i <= end) { if (nums[i] < pivot) { swap(nums, i, start); start++; i++; } else if (nums[i] == pivot) { i++; } else { swap(nums, i, end); end--; } }注意start++后i++, end--后i不用++, 因为start不可能指向2